Question:
When \(SO_2\) gas is passed into aqueous \(Na_2CO_3\) the product(s) formed is(are)
When \(SO_2\) gas is passed into aqueous \(Na_2CO_3\) the product(s) formed is(are)
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This reaction is analogous to passing \(CO_2\) through lime water; first a normal salt forms, and with excess gas, an acid salt (bicarbonate/bisulfite) forms.
Updated On: Apr 29, 2026
- \(NaHSO_4\)
- \(Na_2SO_4\)
- \(NaHSO_3\)
- \(Na_2SO_3\) and \(NaHSO_3\)
- \(NaHSO_4\) and \(Na_2SO_4\)
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The Correct Option is D
Solution and Explanation
Concept:
Sulfur dioxide (\(SO_2\)) is an acidic oxide. When it reacts with a solution of a basic salt like sodium carbonate (\(Na_2CO_3\)), it behaves similarly to \(CO_2\) but is a stronger acid.
Step 1: Reaction with limited \(SO_2\).
Initially, the \(SO_2\) reacts with sodium carbonate to form sodium sulfite and displace carbon dioxide: \[ Na_2CO_3 + SO_2 \rightarrow Na_2SO_3 + CO_2 \uparrow \]
Step 2: Reaction with excess \(SO_2\).
If more \(SO_2\) is passed through the aqueous solution, the sodium sulfite further reacts with the acidic gas and water to form sodium bisulfite (sodium hydrogen sulfite): \[ Na_2SO_3 + H_2O + SO_2 \rightarrow 2NaHSO_3 \]
Step 3: Conclusion.
Depending on the concentration and duration, both sodium sulfite (\(Na_2SO_3\)) and sodium bisulfite (\(NaHSO_3\)) can be present in the reaction mixture.
Step 1: Reaction with limited \(SO_2\).
Initially, the \(SO_2\) reacts with sodium carbonate to form sodium sulfite and displace carbon dioxide: \[ Na_2CO_3 + SO_2 \rightarrow Na_2SO_3 + CO_2 \uparrow \]
Step 2: Reaction with excess \(SO_2\).
If more \(SO_2\) is passed through the aqueous solution, the sodium sulfite further reacts with the acidic gas and water to form sodium bisulfite (sodium hydrogen sulfite): \[ Na_2SO_3 + H_2O + SO_2 \rightarrow 2NaHSO_3 \]
Step 3: Conclusion.
Depending on the concentration and duration, both sodium sulfite (\(Na_2SO_3\)) and sodium bisulfite (\(NaHSO_3\)) can be present in the reaction mixture.
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