Step 1: Reaction type (Nucleophilic substitution).
p-nitrobromobenzene has a strong electron withdrawing \(-NO_2\) group at para position.
This activates benzene ring towards nucleophilic substitution (SNAr). Step 2: Role of sodium ethoxide.
Sodium ethoxide \((C_2H_5O^-Na^+)\) acts as nucleophile.
It replaces bromine on aromatic ring. Step 3: Product formed.
Replacement of Br by \(-OC_2H_5\) gives p-nitrophenetole. Final Answer:
\[
\boxed{\text{p-nitrophenetole}}
\]