Question:
When nitric acid reacts with nitric oxide, a gas is released, which converts $H _{2} S$ into
When nitric acid reacts with nitric oxide, a gas is released, which converts $H _{2} S$ into
Updated On: Mar 30, 2023
- $SO _{4}^{2-}$
- $S ^{2-}$
- $S$
- $S _{2} O _{5}^{2-}$
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The Correct Option is C
Solution and Explanation
When nitric acid $\left( HNO _{3}\right)$ reacts with nitric oxide (NO), $NO _{2}$ gas is released which oxidises $H _{2} S$ into sulphur.
The reactions are as follows :
$2 HNO _{3}+ NO \longrightarrow H _{2} O +3 NO _{2} $
$NO _{2}+ H _{2} S \longrightarrow H _{2} O + S + NO$
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Concepts Used:
P-Block Elements
- P block elements are those in which the last electron enters any of the three p-orbitals of their respective shells. Since a p-subshell has three degenerate p-orbitals each of which can accommodate two electrons, therefore in all there are six groups of p-block elements.
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P block elements consist of:
- Group 13 Elements: Boron family
- Group 14 Elements: Carbon family
- Group 15 Elements: Nitrogen family
- Group 16 Elements: Oxygen family
- Group 17 Elements: Fluorine family
- Group 18 Elements: Neon family