Concept:
Oxidation of MnO$_2$ in alkaline medium produces manganate ion.
Step 1: Reaction mechanism.
\[
MnO_2 + 2KOH + KNO_2 \rightarrow K_2MnO_4 + NO + H_2O
\]
Step 2: Oxidation state change.
Mn: +4 → +6 (oxidation)
Step 3: Colour identification.
• MnO$_4^{2-}$ → green
• MnO$_4^-$ → purple
Step 4: Why others are incorrect.
• (B): KMnO$_4$ formed in further oxidation
• (C), (D), (E): not products of this reaction
Final Conclusion:
Green manganate (K$_2$MnO$_4$) is formed.