Question:
When methanamine is treated with benzoyl chloride, the major product is
When methanamine is treated with benzoyl chloride, the major product is
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Acid chloride + amine → amide formation (Schotten-Baumann reaction).
Updated On: May 8, 2026
- N-phenylethanamide
- N-methylbenzamide
- benzanilide
- acetophenone
- N-ethylethanamide
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The Correct Option is B
Solution and Explanation
Concept:
Amines react with acid chlorides to form amides via Schotten-Baumann reaction.
Step 1: Identify reactants.
• Methanamine: \(CH_3NH_2\)
• Benzoyl chloride: \(C_6H_5COCl\)
Step 2: Reaction mechanism.
• Nitrogen attacks carbonyl carbon
• Chlorine leaves
• Amide is formed
Step 3: Write reaction. \[ CH_3NH_2 + C_6H_5COCl \rightarrow C_6H_5CONHCH_3 + HCl \]
Step 4: Identify product. Product is: \[ \text{N-methylbenzamide} \]
Step 5: Match with options. Correct option is (B). Final Conclusion: \[ \boxed{\text{N-methylbenzamide}} \]
Step 1: Identify reactants.
• Methanamine: \(CH_3NH_2\)
• Benzoyl chloride: \(C_6H_5COCl\)
Step 2: Reaction mechanism.
• Nitrogen attacks carbonyl carbon
• Chlorine leaves
• Amide is formed
Step 3: Write reaction. \[ CH_3NH_2 + C_6H_5COCl \rightarrow C_6H_5CONHCH_3 + HCl \]
Step 4: Identify product. Product is: \[ \text{N-methylbenzamide} \]
Step 5: Match with options. Correct option is (B). Final Conclusion: \[ \boxed{\text{N-methylbenzamide}} \]
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