Question:
When \(KMnO_{4}\) is heated to 513 K the products formed are \(K_{2}MnO_{4}\), \(O_{2}\) and.
When \(KMnO_{4}\) is heated to 513 K the products formed are \(K_{2}MnO_{4}\), \(O_{2}\) and.
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Permanganate is purple, while manganate ($K_2MnO_4$) is green.
Updated On: Apr 27, 2026
- MnO
- $Mn_{2}O_{3}$
- $Mn_{2}O_{7}$
- $MnO_{2}$
- $Mn_{3}O_{4}$
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The Correct Option is D
Solution and Explanation
Step 1: Concept
Thermal decomposition of potassium permanganate.
Step 2: Meaning
Heating $KMnO_4$ at high temperatures results in its breakdown into manganate and oxides of manganese.
Step 3: Analysis
The balanced equation is: $2KMnO_{4} \xrightarrow{\Delta} K_{2}MnO_{4} + MnO_{2} + O_{2}$.
Step 4: Conclusion
The third product formed is manganese dioxide ($MnO_{2}$).
Final Answer: (D)
Thermal decomposition of potassium permanganate.
Step 2: Meaning
Heating $KMnO_4$ at high temperatures results in its breakdown into manganate and oxides of manganese.
Step 3: Analysis
The balanced equation is: $2KMnO_{4} \xrightarrow{\Delta} K_{2}MnO_{4} + MnO_{2} + O_{2}$.
Step 4: Conclusion
The third product formed is manganese dioxide ($MnO_{2}$).
Final Answer: (D)
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