Question:
When ethanamide is treated with \(Br_{2}\) and NaOH in ethanolic solution we get.
When ethanamide is treated with \(Br_{2}\) and NaOH in ethanolic solution we get.
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Hoffmann Degradation: $R-CONH_2 \rightarrow R-NH_2$ (Step-down reaction).
Updated On: Apr 27, 2026
- ethanamine
- bromoethanamide
- bromoethane
- methanamine
- 2-bromoethanamine
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The Correct Option is D
Solution and Explanation
Step 1: Concept
This is the Hoffmann Bromamide Degradation reaction.
Step 2: Meaning
An amide reacts with $Br_{2}$ and an alkali to form a primary amine with one fewer carbon atom.
Step 3: Analysis
Ethanamide ($CH_3CONH_2$) has 2 carbons. Degradation yields an amine with 1 carbon, which is methanamine ($CH_3NH_2$).
Step 4: Conclusion
Hence, the product is methanamine.
Final Answer: (D)
This is the Hoffmann Bromamide Degradation reaction.
Step 2: Meaning
An amide reacts with $Br_{2}$ and an alkali to form a primary amine with one fewer carbon atom.
Step 3: Analysis
Ethanamide ($CH_3CONH_2$) has 2 carbons. Degradation yields an amine with 1 carbon, which is methanamine ($CH_3NH_2$).
Step 4: Conclusion
Hence, the product is methanamine.
Final Answer: (D)
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