Question:
When current in a coil changes from $5 \,A$ to $2 \,A$ in $0.1\, s$, an average voltage of $50\, V$ is produced. The self - inductance of the coil is :
When current in a coil changes from $5 \,A$ to $2 \,A$ in $0.1\, s$, an average voltage of $50\, V$ is produced. The self - inductance of the coil is :
Updated On: Apr 1, 2026
- 0.67 H
- 1.67 H
- 3 H
- 6 H
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The Correct Option is B
Solution and Explanation
According to Faraday?s law of electromagnetic induction,
Induced emf, $e =\frac{Ldi}{dt}$
$50 = L\left(\frac{5-2}{0.1\,sec}\right)$
$\Rightarrow L = \frac{50\times0.1}{3} = \frac{5}{3} = 1.67\, H$
Induced emf, $e =\frac{Ldi}{dt}$
$50 = L\left(\frac{5-2}{0.1\,sec}\right)$
$\Rightarrow L = \frac{50\times0.1}{3} = \frac{5}{3} = 1.67\, H$
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Concepts Used:
Electromagnetic Induction
Electromagnetic Induction is a current produced by the voltage production due to a changing magnetic field. This happens in one of the two conditions:-
- When we place the conductor in a changing magnetic field.
- When the conductor constantly moves in a stationary field.
Formula:
The electromagnetic induction is mathematically represented as:-
e=N × d∅.dt
Where
- e = induced voltage
- N = number of turns in the coil
- Φ = Magnetic flux (This is the amount of magnetic field present on the surface)
- t = time
Applications of Electromagnetic Induction
- Electromagnetic induction in AC generator
- Electrical Transformers
- Magnetic Flow Meter