Question:
When CoCl\(_3\) solution is treated with excess ammonia, a violet coloured complex is formed which conducts current. Also, it gives one mole of AgCl when treated with AgNO\(_3\). What is the chemical formula of the complex
When CoCl\(_3\) solution is treated with excess ammonia, a violet coloured complex is formed which conducts current. Also, it gives one mole of AgCl when treated with AgNO\(_3\). What is the chemical formula of the complex
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The number of chloride ions precipitated by AgNO\(_3\) equals the number of chloride ions outside the coordination sphere.
Updated On: Apr 24, 2026
- [CoCl\(_2\)(NH\(_3\))\(_4\)]Cl
- [CoCl\(_3\)(NH\(_3\))\(_3\)]
- [CoCl(NH\(_3\))\(_5\)]Cl\(_2\)
- [Co(NH\(_3\))\(_6\)]Cl\(_3\)
- [CoCl(NH\(_3\))\(_5\)]Cl\(_2\).H\(_2\)O
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The Correct Option is A
Solution and Explanation
Step 1: Understanding the Concept:
Conductivity indicates the presence of ions in solution. The reaction with AgNO3 tests for chloride ions outside the coordination sphere (free chloride ions).
Step 2: Detailed Explanation:
The complex gives one mole of AgCl per mole of complex. This means only one Cl- ion is free (outside the coordination sphere) and can be precipitated. The complex is violet and conducts current, confirming it is an electrolyte. Let the formula be [Co(NH3)xCly]Clz. The total number of Cl atoms = y + z = 3 (from CoCl3). The number of free Cl- ions = z = 1. Therefore, y = 2. The coordination number of Co(III) is typically 6. So, x + y = 6 => x + 2 = 6 => x = 4. The formula is [CoCl2(NH3)4]Cl.
Step 3: Final Answer:
The chemical formula of the complex is [CoCl2(NH3)4]Cl.
Conductivity indicates the presence of ions in solution. The reaction with AgNO3 tests for chloride ions outside the coordination sphere (free chloride ions).
Step 2: Detailed Explanation:
The complex gives one mole of AgCl per mole of complex. This means only one Cl- ion is free (outside the coordination sphere) and can be precipitated. The complex is violet and conducts current, confirming it is an electrolyte. Let the formula be [Co(NH3)xCly]Clz. The total number of Cl atoms = y + z = 3 (from CoCl3). The number of free Cl- ions = z = 1. Therefore, y = 2. The coordination number of Co(III) is typically 6. So, x + y = 6 => x + 2 = 6 => x = 4. The formula is [CoCl2(NH3)4]Cl.
Step 3: Final Answer:
The chemical formula of the complex is [CoCl2(NH3)4]Cl.
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