Question:
When $CO_2$ is passed through solution of sodium aluminate, precipitate of which compound is formed?
When $CO_2$ is passed through solution of sodium aluminate, precipitate of which compound is formed?
Updated On: Aug 1, 2022
- $Al(OH)_3$
- $Al_2O_3$
- $Na_2CO_3$
- No ppt
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The Correct Option is A
Solution and Explanation
In Hall?? process, for purifying the bauxite ore, the solution containing sodium meta aluminate is warmed to 50-60$^{\circ}$C and carbon dioxide is circulated through it, Al(OH) separates out as precipitate.
$ {2NaAlO2 + CO2 + 3H2O -> 2Al(OH)3 + Na2CO3}$
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Concepts Used:
P-Block Elements
- P block elements are those in which the last electron enters any of the three p-orbitals of their respective shells. Since a p-subshell has three degenerate p-orbitals each of which can accommodate two electrons, therefore in all there are six groups of p-block elements.
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P block elements consist of:
- Group 13 Elements: Boron family
- Group 14 Elements: Carbon family
- Group 15 Elements: Nitrogen family
- Group 16 Elements: Oxygen family
- Group 17 Elements: Fluorine family
- Group 18 Elements: Neon family