Question:

When a string is divided into three segments of length \(l_1, l_2,\) and \(l_3\), the fundamental frequencies of these three segments are \(v_1, v_2,\) and \(v_3\) respectively. The original fundamental frequency of the string is:

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For strings under same tension, frequency is inversely proportional to length.
Updated On: Mar 24, 2026
  • \(\sqrt{v} = \sqrt{v_1} + \sqrt{v_2} + \sqrt{v_3}\)
  • \(v = v_1 + v_2 + v_3\)
  • \(\dfrac{1}{v} = \dfrac{1}{v_1} + \dfrac{1}{v_2} + \dfrac{1}{v_3}\)
  • \(\dfrac{1}{\sqrt{v}} = \dfrac{1}{\sqrt{v_1}} + \dfrac{1}{\sqrt{v_2}} + \dfrac{1}{\sqrt{v_3}}\)
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The Correct Option is C

Solution and Explanation


Step 1:
For a stretched string, fundamental frequency: \[ v \propto \frac{1}{l} \]
Step 2:
Hence, \[ v_1 \propto \frac{1}{l_1},\quad v_2 \propto \frac{1}{l_2},\quad v_3 \propto \frac{1}{l_3} \]
Step 3:
Total length \(l = l_1 + l_2 + l_3\): \[ \frac{1}{v} \propto l_1 + l_2 + l_3 \] \[ \Rightarrow \frac{1}{v} = \frac{1}{v_1} + \frac{1}{v_2} + \frac{1}{v_3} \]
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