Question

When a particle in linear S.H.M. completes two oscillations, its phase changes by

• A. \(2\pi\) radian
• B. \(4\pi\) radian
• C. \(\pi\) radian
• D. \(3\pi\) radian

Hint:

The phase increases by 2 pi radian for each complete oscillation.

Answer 1

The Correct Option is B

Step 1: Understanding the Concept
In S.H.M. the phase is \(\omega t+\phi\). In one complete oscillation, the time is \(T=\dfrac{2\pi}{\omega}\), so the phase increases by \(2\pi\).

Step 2: Calculation
For two oscillations, the time is \(2T\) and the phase change is \(\omega\times2T=4\pi\) radian.

Step 3: Final answer
The phase changes by \(4\pi\) radian.

Final Answer:
The phase changes by 4 pi radian. \[ \boxed{\text{(B) }4\pi\ \text{radian}} \]