When a hydrocarbon A undergoes complete combustion it requires 11 equivalents of oxygen and produces 4 equivalents of water. What is the molecular formula of $A$?
Hydrocarbon will be
So, the correct option is (D): \(C_9H_8\)
Let the molecular formula of the hydrocarbon be \( C_xH_y \). The balanced combustion reaction is:
\[ C_xH_y + \left( \frac{x + \frac{y}{4}}{2} \right) O_2 \rightarrow x \, CO_2 + \frac{y}{2} \, H_2O \]
We are given that 11 equivalents of oxygen are required, and 4 equivalents of water are produced. Using stoichiometry:
\[ \frac{y}{2} = 4 \quad \Rightarrow \quad y = 8 \]
Substituting in the oxygen requirement:
\[ x + \frac{8}{4} = 11 \quad \Rightarrow \quad x + 2 = 22 \quad \Rightarrow \quad x = 9 \]
Thus, the molecular formula is \( C_9H_8 \).
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)

Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,
Read More: Some Basic Concepts of Chemistry
There are two ways of classifying the matter:
Matter can exist in three physical states:
Based upon the composition, matter can be divided into two main types: