When a hydrocarbon A undergoes complete combustion it requires 11 equivalents of oxygen and produces 4 equivalents of water. What is the molecular formula of $A$?
Hydrocarbon will be
So, the correct option is (D): \(C_9H_8\)
Let the molecular formula of the hydrocarbon be \( C_xH_y \). The balanced combustion reaction is:
\[ C_xH_y + \left( \frac{x + \frac{y}{4}}{2} \right) O_2 \rightarrow x \, CO_2 + \frac{y}{2} \, H_2O \]
We are given that 11 equivalents of oxygen are required, and 4 equivalents of water are produced. Using stoichiometry:
\[ \frac{y}{2} = 4 \quad \Rightarrow \quad y = 8 \]
Substituting in the oxygen requirement:
\[ x + \frac{8}{4} = 11 \quad \Rightarrow \quad x + 2 = 22 \quad \Rightarrow \quad x = 9 \]
Thus, the molecular formula is \( C_9H_8 \).
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)

Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)
Read More: Some Basic Concepts of Chemistry
There are two ways of classifying the matter:
Matter can exist in three physical states:
Based upon the composition, matter can be divided into two main types: