When a bio chemical reaction is carried out in laboratory out side the human body in the absence of enzyme, then the rate of reaction obtained is \(10^–6\) times, than activation energy of reaction in the presence of enzyme is
\(\frac{6}{RT}\)
Different from, Ea obtained in laboratery
Can't say anything
The correct option is(C): Different from, Ea obtained in laboratery.
The rate of reaction obtained in the absence of enzymes (in the laboratory) is \(10^–6\) times slower than the rate in the presence of enzymes. The activation energy (Ea) obtained in the laboratory is different from the activation energy (Ea) observed in biological systems. This difference arises because enzymes lower the activation energy barrier, facilitating reactions in biological contexts.
(i) Write any two differences between order and molecularity.
(ii) What do you mean by pseudo order reaction?
Given below are two statements:
Statement I: Transfer RNAs and ribosomal RNA do not interact with mRNA.
Statement II: RNA interference (RNAi) takes place in all eukaryotic organisms as a method of cellular defence.
In the light of the above statements, choose the most appropriate answer from the options given below:
The rate of a chemical reaction is defined as the change in concentration of any one of the reactants or products per unit time.
Consider the reaction A → B,
Rate of the reaction is given by,
Rate = −d[A]/ dt=+d[B]/ dt
Where, [A] → concentration of reactant A
[B] → concentration of product B
(-) A negative sign indicates a decrease in the concentration of A with time.
(+) A positive sign indicates an increase in the concentration of B with time.
There are certain factors that determine the rate of a reaction: