Concept:
The median is a measure of central tendency which represents:
\[
\text{The middle value of an ordered data set}
\]
Rules for finding median:
• Arrange the observations in ascending order.
• If the number of observations \(n\) is odd:
\[
\text{Median} = \left(\frac{n+1}{2}\right)^{th} \text{ observation}
\]
• If \(n\) is even:
\[
\text{Median} = \frac{\text{middle two observations}}{2}
\]
Step 1: Writing the given observations.
The given weights are:
\[
70,\; 54,\; 45,\; 50,\; 68,\; 47,\; 75,\; 56,\; 55,\; 60,\; 72,\; 68,\; 66,\; 59,\; 57,\; 48
\]
Total number of observations:
\[
n = 16
\]
Since:
\[
n = 16
\]
which is an even number, we must find:
\[
\text{Average of the 8th and 9th observations}
\]
Step 2: Arranging the data in ascending order.
After arranging:
\[
45,\; 47,\; 48,\; 50,\; 54,\; 55,\; 56,\; 57,\; 59,\; 60,\; 66,\; 68,\; 68,\; 70,\; 72,\; 75
\]
Now identify:
\[
8^{th} \text{ and } 9^{th} \text{ observations}
\]
\[
8^{th} = 57
\]
\[
9^{th} = 59
\]
Step 3: Calculating the median.
Median:
\[
= \frac{57+59}{2}
\]
\[
= \frac{116}{2}
\]
\[
= 58
\]
Step 4: Final conclusion.
Therefore, the median of the given data is:
\[
\boxed{58}
\]
Hence, the correct answer is:
\[
\boxed{\text{(A) }58}
\]