Question:
What will be the genotype of a carrier individual who shows sickle cell anaemic trait?
What will be the genotype of a carrier individual who shows sickle cell anaemic trait?
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{Hb$^{A}$Hb$^{S}$ = carrier}, {Hb$^{S}$Hb$^{S}$ = diseased}.
Updated On: Mar 28, 2026
- Hb$^{B}$ Hb$^{B}$
- Hb$^{A}$ Hb$^{S}$
- Hb$^{S}$ Hb$^{S}$
- Hb$^{A}$ Hb$^{A}$
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The Correct Option is B
Solution and Explanation
Step 1: Understanding sickle cell anaemia.
Sickle cell anaemia is a genetic disorder caused by a mutation in the gene coding for haemoglobin.
Step 2: Identifying the carrier genotype.
A carrier individual has one normal haemoglobin allele (Hb$^{A}$) and one sickle allele (Hb$^{S}$). Such individuals usually do not show severe symptoms.
Step 3: Conclusion.
Therefore, the genotype of a carrier individual is Hb$^{A$ Hb$^{S}$}.
Sickle cell anaemia is a genetic disorder caused by a mutation in the gene coding for haemoglobin.
Step 2: Identifying the carrier genotype.
A carrier individual has one normal haemoglobin allele (Hb$^{A}$) and one sickle allele (Hb$^{S}$). Such individuals usually do not show severe symptoms.
Step 3: Conclusion.
Therefore, the genotype of a carrier individual is Hb$^{A$ Hb$^{S}$}.
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