Step 1: Understanding the Question:
Ethoxy ethane (\(C_2H_5-O-C_2H_5\)) and methoxy propane (\(CH_3-O-CH_2CH_2CH_3\)) both have the molecular formula \(C_4H_{10}O\). We need the type of isomerism.
Step 2: Key Formula or Approach:
Metamerism is a type of isomerism where compounds have the same functional group but different alkyl groups on either side of the functional group (for ethers, thioethers, etc.).
Step 3: Detailed Explanation:
- Both are ethers (same functional group –O–).
- Ethoxy ethane has ethyl groups on both sides.
- Methoxy propane has a methyl group and a propyl group.
They differ in the distribution of alkyl groups around the oxygen atom, which is metamerism.
They are not tautomers, position isomers (skeleton same? no), or functional group isomers (same functional group).
Step 4: Final Answer:
The correct answer is metamers, option (B).