Step 1: Understanding the Concept
Benzylic halides have the halogen on an sp3 carbon that is directly bonded to an aromatic ring. Allylic halides have it next to a C=C bond.
Step 2: Analyse the structure
In \(\text{C}_{6}\text{H}_{5}\text{CH}_{2}\text{Br}\), bromine is on the \(\text{CH}_{2}\) carbon, which is attached to the benzene ring.
Step 3: Conclusion
Aryl and vinylic halides have the halogen on an sp2 carbon, so they do not fit. The compound is a benzylic halide.
Final Answer:
\(\text{C}_{6}\text{H}_{5}\text{CH}_{2}\text{Br}\) is a benzylic halide.
\[ \boxed{\text{(B) }\text{benzylic}} \]