What is X in the following reaction?
What is X in the following reaction?
Show Hint
- Butan-2-ol
- 2-methyl propan-2-ol
- 2-Methyl propan-1-ol
- Butan-1-ol
The Correct Option is B
Solution and Explanation
The reactant is a tertiary alkyl halide, 2-bromo-2-methylpropane.
2. Identify the reaction type:
The reaction involves an alkyl halide reacting with a strong nucleophile (OH\(^{-}\)).
Since the reactant is a tertiary alkyl halide, the reaction will proceed via an S\(_N\)1 mechanism.
In an S\(_N\)1 reaction, the leaving group (Br\(^{-}\)) departs first, forming a carbocation intermediate.
The nucleophile (OH\(^{-}\)) then attacks the carbocation.
The product formed will have the OH group attached to the carbon that was bonded to the bromine.
The carbocation formed is a tertiary carbocation.
The OH\(^{-}\) attacks the carbocation, resulting in the formation of 2-methylpropan-2-ol.
Therefore, X is 2-methylpropan-2-ol.
Final Answer:2-methylpropan-2-ol.
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