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what is the x coordinate of the point on the curve
Question:
What is the x-coordinate of the point on the curve
f(x)=√(x)(7x-6),
where the tangent is parallel to x-axis?
Show Hint
Horizontal tangent ⟹ f'(x)=0.
BITSAT - 2020
BITSAT
Updated On:
Mar 19, 2026
\(-\dfrac{1}{3}\)
\(\dfrac{2}{7}\)
\(\dfrac{6}{7}\)
(1)/(2)
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The Correct Option is
C
Solution and Explanation
Tangent parallel to x-axis ⟹ f'(x)=0. Differentiating: f'(x)=\frac7x-62√(x)+7√(x) Setting f'(x)=0: 7x-6+14x=0 ⟹ 21x=6 ⟹ x=(6)/(7)
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