Question:
What is the work done when an ideal gas (0.300 mol) expands in vacuum?
What is the work done when an ideal gas (0.300 mol) expands in vacuum?
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Work done against zero external pressure is zero.
Updated On: Nov 12, 2026
- zero
- one
- two
- three
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The Correct Option is A
Solution and Explanation
Step 1: Understanding the Concept
Pressure-volume work is \(w=-p_{ext}\Delta V\).
Step 2: Expansion in vacuum
In a vacuum there is nothing to push against, so the external pressure is zero: \(p_{ext}=0\).
Step 3: Result
Hence \(w=-0\times\Delta V=0\), whatever the amount of gas or the change in volume.
Final Answer:
The work done in free expansion is zero, which is option (A). \[ \boxed{\text{(A) }\text{zero}} \]
Pressure-volume work is \(w=-p_{ext}\Delta V\).
Step 2: Expansion in vacuum
In a vacuum there is nothing to push against, so the external pressure is zero: \(p_{ext}=0\).
Step 3: Result
Hence \(w=-0\times\Delta V=0\), whatever the amount of gas or the change in volume.
Final Answer:
The work done in free expansion is zero, which is option (A). \[ \boxed{\text{(A) }\text{zero}} \]
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