Question:

What is the volume occupied by 16 g methane gas at STP?

Show Hint

Remember: STP conditions (0°C, 1 atm) give molar volume 22.4 L for any ideal gas. Always check the units – here cm³ is required, so convert L to cm³ (1 L = 1000 cm³).
Updated On: Jun 4, 2026
  • \( 1140 \, \text{cm}^3 \)
  • \( 22400 \, \text{cm}^3 \)
  • \( 214 \, \text{cm}^3 \)
  • \( 12.4 \, \text{cm}^3 \)
Show Solution
collegedunia
Verified By Collegedunia

The Correct Option is B

Solution and Explanation

Step 1: Understanding the Question:
We need the volume at STP (Standard Temperature and Pressure) for 16 g of methane gas (\(CH_4\)).

Step 2: Key Formula or Approach:
At STP, 1 mole of any ideal gas occupies 22.4 L = 22400 cm³. Molar mass of \(CH_4\) = 12 + 4×1 = 16 g/mol.

Step 3: Detailed Explanation:
Mass given = 16 g. Number of moles = \( \frac{16}{16} = 1 \) mol. Volume = 1 mol × 22400 cm³/mol = 22400 cm³.

Step 4: Final Answer:
The volume is 22400 cm³, option (B).
Was this answer helpful?
0
0