Step 1: Understanding the Question:
We need the volume at STP (Standard Temperature and Pressure) for 16 g of methane gas (\(CH_4\)).
Step 2: Key Formula or Approach:
At STP, 1 mole of any ideal gas occupies 22.4 L = 22400 cm³. Molar mass of \(CH_4\) = 12 + 4×1 = 16 g/mol.
Step 3: Detailed Explanation:
Mass given = 16 g. Number of moles = \( \frac{16}{16} = 1 \) mol. Volume = 1 mol × 22400 cm³/mol = 22400 cm³.
Step 4: Final Answer:
The volume is 22400 cm³, option (B).