Question:
What is the volume occupied by \(0.5\text{ mol}\) of \(\text{CO}_2\) at STP?
What is the volume occupied by \(0.5\text{ mol}\) of \(\text{CO}_2\) at STP?
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At STP: Volume = moles à 22.4 dm$^3$.
Updated On: Apr 26, 2026
- \(5.6\text{ dm}^3\)
- \(11.2\text{ dm}^3\)
- \(16.8\text{ dm}^3\)
- \(22.4\text{ dm}^3\)
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The Correct Option is B
Solution and Explanation
Concept:
At STP (0°C, 1 atm): \[ 1 \text{ mole of gas} = 22.4 \text{ dm}^3 \] Step 1: Use proportional relation. \[ 1 \text{ mole} \rightarrow 22.4 \text{ dm}^3 \] \[ 0.5 \text{ mole} \rightarrow ? \]
Step 2: Calculate. \[ 0.5 \times 22.4 = 11.2 \text{ dm}^3 \]
Step 3: Conclusion. \[ \text{Volume} = 11.2 \text{ dm}^3 \]
At STP (0°C, 1 atm): \[ 1 \text{ mole of gas} = 22.4 \text{ dm}^3 \] Step 1: Use proportional relation. \[ 1 \text{ mole} \rightarrow 22.4 \text{ dm}^3 \] \[ 0.5 \text{ mole} \rightarrow ? \]
Step 2: Calculate. \[ 0.5 \times 22.4 = 11.2 \text{ dm}^3 \]
Step 3: Conclusion. \[ \text{Volume} = 11.2 \text{ dm}^3 \]
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