Question:
What is the Van’t Hoff factor (\(i\)) for a completely dissociated solution of \(K_2SO_4\) in water?
What is the Van’t Hoff factor (\(i\)) for a completely dissociated solution of \(K_2SO_4\) in water?
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Van’t Hoff factor equals the number of ions produced after complete dissociation.
Examples:
\(NaCl \rightarrow Na^+ + Cl^-\) → \(i = 2\)
\(CaCl_2 \rightarrow Ca^{2+} + 2Cl^-\) → \(i = 3\)
\(K_2SO_4 \rightarrow 2K^+ + SO_4^{2-}\) → \(i = 3\)
Updated On: Apr 22, 2026
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The Correct Option is C
Solution and Explanation
Concept:
The Van’t Hoff factor (\(i\)) represents the number of particles formed when one formula unit of a solute dissociates in solution.
\[
i = \text{Total number of ions produced after dissociation}
\]
Step 1: Write the dissociation reaction of \(K_2SO_4\). \[ K_2SO_4 \rightarrow 2K^+ + SO_4^{2-} \]
Step 2: Count the number of ions produced. \[ 2K^+ + SO_4^{2-} \] Total ions produced: \[ 2 + 1 = 3 \]
Step 3: Determine the Van’t Hoff factor. \[ i = 3 \] \[ \boxed{i = 3} \]
Step 1: Write the dissociation reaction of \(K_2SO_4\). \[ K_2SO_4 \rightarrow 2K^+ + SO_4^{2-} \]
Step 2: Count the number of ions produced. \[ 2K^+ + SO_4^{2-} \] Total ions produced: \[ 2 + 1 = 3 \]
Step 3: Determine the Van’t Hoff factor. \[ i = 3 \] \[ \boxed{i = 3} \]
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