Question:
What is the unit of rate constant for a second order reaction?
What is the unit of rate constant for a second order reaction?
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General rule: Unit of \(k = (mol \, L^{-1})^{1-n} s^{-1}\)
Updated On: Apr 24, 2026
- \(mol^2 \, L^{-1} s^{-1}\)
- \(mol^{-1} L^{-1} s^{-1}\)
- \(mol^{-1} L \, s^{-1}\)
- \(mol \, L^2 s^{-1}\)
- \(mol \, L^{-1} s^{-1}\)
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The Correct Option is C
Solution and Explanation
Concept:
Rate law:
\[
\text{Rate} = k[A]^n
\]
Step 1: Write units of rate.
\[ \text{Rate} = mol \, L^{-1} s^{-1} \]
Step 2: For second order reaction (\(n=2\)).
\[ k = \frac{mol \, L^{-1} s^{-1}}{(mol \, L^{-1})^2} \]
Step 3: Simplify units.
\[ k = mol^{-1} L \, s^{-1} \]
Step 1: Write units of rate.
\[ \text{Rate} = mol \, L^{-1} s^{-1} \]
Step 2: For second order reaction (\(n=2\)).
\[ k = \frac{mol \, L^{-1} s^{-1}}{(mol \, L^{-1})^2} \]
Step 3: Simplify units.
\[ k = mol^{-1} L \, s^{-1} \]
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