Question:
What is the unit of first order rate constant?
What is the unit of first order rate constant?
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For first order reactions, the unit of rate constant is always \(s^{-1}\) or generally time\(^{-1}\).
Updated On: May 18, 2026
- Concentration\(^{-1}\) time\(^{-1}\)
- Molar\(^{-1}\) time\(^{-1}\)
- Concentration\(^{-1}\)
- Time\(^{-1}\)
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The Correct Option is D
Solution and Explanation
Concept:
For a first order reaction, the rate of reaction depends directly on the concentration of one reactant.
Step 1: Write the rate law. \[ \text{Rate}=k[A] \]
Step 2: Rearrange for \(k\). \[ k=\frac{\text{Rate}}{[A]} \]
Step 3: Substitute units.
The unit of rate is: \[ \text{concentration}\times \text{time}^{-1} \] The unit of concentration is: \[ \text{concentration} \] Therefore, \[ k=\frac{\text{concentration}\times \text{time}^{-1}}{\text{concentration}} \] \[ k=\text{time}^{-1} \] Hence, the unit of first order rate constant is: \[ \text{time}^{-1} \] \[ \therefore \text{Correct Answer is (D)} \]
For a first order reaction, the rate of reaction depends directly on the concentration of one reactant.
Step 1: Write the rate law. \[ \text{Rate}=k[A] \]
Step 2: Rearrange for \(k\). \[ k=\frac{\text{Rate}}{[A]} \]
Step 3: Substitute units.
The unit of rate is: \[ \text{concentration}\times \text{time}^{-1} \] The unit of concentration is: \[ \text{concentration} \] Therefore, \[ k=\frac{\text{concentration}\times \text{time}^{-1}}{\text{concentration}} \] \[ k=\text{time}^{-1} \] Hence, the unit of first order rate constant is: \[ \text{time}^{-1} \] \[ \therefore \text{Correct Answer is (D)} \]
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