Question:
What is the total number of orbitals associated with the principal quantum number $n=3$? ________.
What is the total number of orbitals associated with the principal quantum number $n=3$? ________.
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Total orbitals $= n^2$; Total electrons $= 2n^2$.
Updated On: Jun 26, 2026
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The Correct Option is C
Solution and Explanation
Step 1: Concept
The total number of orbitals in a shell with principal quantum number $n$ is $n^2$.
Step 2: Meaning
For $n=3$, the subshells are $3s$ ($l=0$), $3p$ ($l=1$), and $3d$ ($l=2$).
Step 3: Analysis
Orbitals: $1 \text{ (from } s) + 3 \text{ (from } p) + 5 \text{ (from } d) = 9$.
Step 4: Conclusion
$3^2 = 9$. Final Answer: (C)
The total number of orbitals in a shell with principal quantum number $n$ is $n^2$.
Step 2: Meaning
For $n=3$, the subshells are $3s$ ($l=0$), $3p$ ($l=1$), and $3d$ ($l=2$).
Step 3: Analysis
Orbitals: $1 \text{ (from } s) + 3 \text{ (from } p) + 5 \text{ (from } d) = 9$.
Step 4: Conclusion
$3^2 = 9$. Final Answer: (C)
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