Question:
What is the total number of donor atoms present in Tetracyanonickelate(II) ion?
What is the total number of donor atoms present in Tetracyanonickelate(II) ion?
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"Tetra" = 4. Monodentate ligands contribute 1 donor atom each.
Updated On: May 14, 2026
- 2
- 4
- 6
- 1
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The Correct Option is B
Solution and Explanation
Step 1: Concept The number of donor atoms corresponds to the coordination number if the ligands are monodentate.
Step 2: Meaning The ion is $[\text{Ni(CN)}_4]^{2-}$.
Step 3: Analysis Cyanide ($\text{CN}^-$) is a monodentate ligand, meaning each cyanide ion has one donor atom (carbon) that coordinates with the nickel.
Step 4: Conclusion Since there are four cyanide ligands, there are a total of 4 donor atoms. Final Answer: (B)
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