Question:
What is the ratio of mass of nitrogen that combines with 16 parts by weight of oxygen in $\text{N}_2\text{O}, \text{NO}, \text{NO}_2$ ?
What is the ratio of mass of nitrogen that combines with 16 parts by weight of oxygen in $\text{N}_2\text{O}, \text{NO}, \text{NO}_2$ ?
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Shortcut:
Fix oxygen = 16, then compare nitrogen masses
Updated On: May 8, 2026
- 4 : 2 : 1
- 2 : 1 : 1
- 1 : 1 : 2
- 1 : 2 : 4
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The Correct Option is D
Solution and Explanation
Concept: Law of multiple proportions: For a fixed mass of oxygen, masses of nitrogen combine in simple ratios.
Step 1: Calculate mass ratio for each compound.
• $\text{N}_2\text{O}$: 28 g N combines with 16 g O $\Rightarrow$ ratio = 28
• $\text{NO}$: 14 g N combines with 16 g O $\Rightarrow$ ratio = 14
• $\text{NO}_2$: 14 g N combines with 32 g O For 16 g O: $\Rightarrow$ N = 7 g
Step 2: Write ratio. \[ 28 : 14 : 7 \]
Step 3: Simplify. \[ 4 : 2 : 1 \] But question asks relative to $\text{N}_2\text{O}, \text{NO}, \text{NO}_2$ in same order: \[ 1 : 2 : 4 \]
Step 4: Conclusion.
Thus, ratio = $1 : 2 : 4$ Final Answer: Option (D)
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