Question

What is the product of the reaction between Benzene and \(CH_3Cl\) in the presence of anhydrous \(AlCl_3\)?

• A. Toluene
• B. Phenol
• C. Chlorobenzene
• D. Benzaldehyde

Hint:

Friedel–Crafts alkylation introduces an alkyl group onto a benzene ring using a Lewis acid catalyst like \(AlCl_3\).

Answer 1

The Correct Option is A

Concept: This reaction is known as Friedel–Crafts Alkylation, where an alkyl group substitutes a hydrogen atom of the benzene ring in the presence of a Lewis acid catalyst such as \(AlCl_3\).

Step 1: Formation of electrophile. In the presence of \(AlCl_3\), methyl chloride forms a methyl carbocation. \[ CH_3Cl + AlCl_3 \rightarrow CH_3^+ + AlCl_4^- \]

Step 2: Electrophilic substitution on benzene. The methyl carbocation attacks the benzene ring, replacing one hydrogen atom. \[ C_6H_6 + CH_3^+ \rightarrow C_6H_5CH_3 \]

Step 3: Product formation. The product formed is Toluene.