Question:

What is the probability of producing a colourblind son if a colourblind male marries a normal visioned female?

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Sons receive their X chromosome from the mother and the Y chromosome from the father.
Updated On: Nov 13, 2026
  • zero

  • \(\frac{1}{4}^{\text{th }}\)

  • \(\frac{1}{2}\)

  • 1

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The Correct Option is A

Solution and Explanation

Step 1: Understanding the Concept
Colour blindness is X-linked recessive.
Colourblind male is \(X^cY\) and a normal visioned female is \(XX\).

Step 2: Cross
Gametes of father: \(X^c\) and \(Y\).
Gametes of mother: \(X\) and \(X\).
Offspring: \(XX^c\) (carrier daughters) and \(XY\) (normal sons).

Step 3: Result
Every son gets normal X from the mother, so the probability of a colourblind son is zero.

Final Answer:
The probability of a colourblind son is zero. \[ \boxed{\text{(A) }\text{zero}} \]
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