Question

What is the percentage of alcohol in a mixture obtained by mixing 5 Lof 25%, 3 Lof 40% and 2Lof 15% alcohol?

• A. 27.5% v/v
• B. 30.5% v/v
• C. 25.5% v/v
• D. 26.5% v/v

Answer 1

The Correct Option is A

To find the percentage of alcohol in the mixture, we need to calculate the total volume of alcohol in the mixture and divide it by the total volume of the mixture. We can follow these steps:

1. Determine the amount of alcohol in each component of the mixture:
   • For the 5 L of 25% alcohol, the volume of alcohol is \(5 \times \frac{25}{100} = 1.25 \, \text{L}\). 
   • For the 3 L of 40% alcohol, the volume of alcohol is \(3 \times \frac{40}{100} = 1.2 \, \text{L}\).
   • For the 2 L of 15% alcohol, the volume of alcohol is \(2 \times \frac{15}{100} = 0.3 \, \text{L}\).
2. Add all the individual volumes of alcohol to get the total volume of alcohol in the mixture:
   • Total volume of alcohol = \(1.25 + 1.2 + 0.3 = 2.75 \, \text{L}\).
3. Calculate the total volume of the mixture:
   • Total volume of mixture = \(5 + 3 + 2 = 10 \, \text{L}\).
4. Calculate the percentage of alcohol by dividing the total volume of alcohol by the total volume of the mixture and multiplying by 100:
   • Percentage of alcohol = \(\left(\frac{2.75}{10}\right) \times 100 = 27.5\% \, v/v\).

Thus, the percentage of alcohol in the mixture is 27.5% v/v, which matches the provided correct answer.