Question:

What is the oxidation state of chromium in the final product when KI reacts with acidified potassium dichromate solution?

Show Hint

Dichromate oxidises iodide to iodine and itself becomes Cr3+.
Updated On: Oct 1, 2026
  • \(+2\)
  • \(+3\)
  • \(+6\)
  • \(+4\)
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The Correct Option is B

Solution and Explanation

Step 1: Write the reaction
Acidified \(K_2Cr_2O_7\) oxidises \(I^-\) to \(I_2\): \(Cr_2O_7^{2-} + 14H^+ + 6I^- \rightarrow 2Cr^{3+} + 3I_2 + 7H_2O\).

Step 2: Oxidation state
In \(Cr_2O_7^{2-}\) chromium is \(+6\). The product \(Cr^{3+}\) has oxidation state \(+3\), so each Cr gains 3 electrons.

Step 3: Other options
\(+6\) is the starting value and \(+2\) or \(+4\) are not formed in this reaction.

Final Answer:
Chromium ends as Cr(III), oxidation state +3. \[ \boxed{\text{(B)}\ +3} \]
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