Question:
What is the oxidation state and coordination number of platinum respectively in
\[
\left[\mathrm{Pt(NH_3)_6}\right]^{4+}\,?
\]
What is the oxidation state and coordination number of platinum respectively in
\[ \left[\mathrm{Pt(NH_3)_6}\right]^{4+}\,? \]
\[ \left[\mathrm{Pt(NH_3)_6}\right]^{4+}\,? \]
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Neutral ligands like \(\mathrm{NH_3}\) do not affect oxidation state but always count toward coordination number.
Updated On: Feb 18, 2026
- \(+6\) and \(4\)
- \(+4\) and \(4\)
- \(+6\) and \(6\)
- \(+4\) and \(6\)
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The Correct Option is D
Solution and Explanation
Step 1: Determine oxidation state of platinum.
In the complex \(\left[\mathrm{Pt(NH_3)_6}\right]^{4+}\), ammonia is a neutral ligand.
Let the oxidation state of Pt be \(x\). Then:
\[ x + 6(0) = +4 \Rightarrow x = +4 \]
Step 2: Determine coordination number.
The coordination number is equal to the number of ligands directly bonded to the metal ion. Here, six \(\mathrm{NH_3}\) ligands are attached to platinum.
Step 3: Conclusion.
Thus, the oxidation state of platinum is \(+4\) and the coordination number is \(6\).
In the complex \(\left[\mathrm{Pt(NH_3)_6}\right]^{4+}\), ammonia is a neutral ligand.
Let the oxidation state of Pt be \(x\). Then:
\[ x + 6(0) = +4 \Rightarrow x = +4 \]
Step 2: Determine coordination number.
The coordination number is equal to the number of ligands directly bonded to the metal ion. Here, six \(\mathrm{NH_3}\) ligands are attached to platinum.
Step 3: Conclusion.
Thus, the oxidation state of platinum is \(+4\) and the coordination number is \(6\).
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