Question:
What is the oxidation number of phosphorus in \(\text{Mg}_{2}\text{P}_{2}\text{O}_{7}\)?
What is the oxidation number of phosphorus in \(\text{Mg}_{2}\text{P}_{2}\text{O}_{7}\)?
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The compound is neutral: 2 times Mg(+2) plus 2 times P plus 7 times O(-2) equals zero.
Updated On: Nov 12, 2026
- \(+3\)
- \(-3\)
- \(+7\)
- \(+5\)
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Verified By Collegedunia
The Correct Option is D
Solution and Explanation
Step 1: Understanding the Concept
In a neutral compound the oxidation numbers of all atoms add up to zero. Mg is +2 and O is -2.
Step 2: Set up the equation
Let the oxidation number of P be \(x\).
\(2(+2)+2x+7(-2)=0\)
Step 3: Solve
\(4+2x-14=0\Rightarrow 2x=10\Rightarrow x=+5\)
Final Answer:
Phosphorus is in the +5 oxidation state. \[ \boxed{\text{(D) }+5} \]
In a neutral compound the oxidation numbers of all atoms add up to zero. Mg is +2 and O is -2.
Step 2: Set up the equation
Let the oxidation number of P be \(x\).
\(2(+2)+2x+7(-2)=0\)
Step 3: Solve
\(4+2x-14=0\Rightarrow 2x=10\Rightarrow x=+5\)
Final Answer:
Phosphorus is in the +5 oxidation state. \[ \boxed{\text{(D) }+5} \]
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