Step 1: Understanding the Concept
Each F atom has 9 electrons, so \(\text{F}_2\) has 18 electrons to place in molecular orbitals.
Step 2: MO Configuration
\(\sigma1s^{2}\,\sigma^{*}1s^{2}\,\sigma2s^{2}\,\sigma^{*}2s^{2}\,\sigma2p_z^{2}\,\pi2p_x^{2}\pi2p_y^{2}\,\pi^{*}2p_x^{2}\pi^{*}2p_y^{2}\)
Step 3: Count the electrons
Bonding: \(2+2+2+4=10\).
Antibonding: \(2+2+4=8\).
Step 4: Check
Bond order \(=\dfrac{10-8}{2}=1\), which matches the single F-F bond.
Final Answer:
\(\text{F}_2\) has 10 bonding and 8 antibonding electrons.
\[ \boxed{\text{(B) }\text{10 and 8}} \]