Step 1: Understanding the Concept
The number of electrons gained by an atom equals the fall in its oxidation number. We calculate the oxidation number of chlorine in both ions.
Step 2: Chlorine in \(\text{ClO}_4^-\)
\[ x+4(-2)=-1\Rightarrow x=+7 \]
Step 3: Chlorine in \(\text{ClO}_2^-\)
\[ y+2(-2)=-1\Rightarrow y=+3 \]
Step 4: Electrons per Cl atom
\[ +7\to+3\ \text{means}\ 4\ \text{electrons gained per atom} \]
Step 5: For n moles
One mole of Cl atoms gains 4 moles of electrons. So \(n\) mol of \(\text{ClO}_4^-\) gain \(4n\) mol of electrons.
Step 6: Check the options
The other options 3n, n and 2n come from wrong oxidation numbers such as +6 or +5 for the product. The correct answer is option (B).
Final Answer:
Each Cl atom goes from +7 to +3, gaining 4 electrons, so n mol gain 4n electrons, option (B).
\[ \boxed{4n} \]