Given: Mass of the sphere, \( M \)
Radius of the sphere, \( R \)
Step 1: Formula for Moment of Inertia of a Solid Sphere The moment of inertia of a solid sphere about an axis passing through its diameter is given by the formula: \[ I = \frac{2}{5} M R^2 \] where: - \( M \) is the mass of the sphere, - \( R \) is the radius of the sphere.
Step 2: Conclusion Thus, the moment of inertia of the solid sphere about its diameter is \( \frac{2}{5} M R^2 \).
Answer: The correct answer is option (a): \( \frac{2}{5} M R^2 \).
For a uniform rectangular sheet shown in the figure, the ratio of moments of inertia about the axes perpendicular to the sheet and passing through \( O \) (the center of mass) and \( O' \) (corner point) is:
