Question:

What is the molarity of pure acetic acid? Assume density of acetic acid = 1 g/ml and Molecular Weight = 60 g/mol.

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For pure liquids, Molarity = (Density $\times$ 1000) Molar Mass.
Updated On: May 13, 2026
  • 12.7
  • 16.7
  • 20.7
  • 55.5
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The Correct Option is B

Solution and Explanation


Step 1: Concept

Molarity ($M$) is defined as the number of moles of solute per liter of solution.

Step 2: Meaning

Density = 1 g/ml means 1000 g of acetic acid exists in 1000 ml (1 Liter) of volume.

Step 3: Analysis

Number of moles = Mass Molar Mass = $1000 \text{ g} / 60 \text{ g/mol} = 16.666...$ moles. Since this is in 1 Liter, $M = 16.7$.

Step 4: Conclusion

The molarity of pure acetic acid under these conditions is 16.7 M. Final Answer: (B)
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