To solve the problem of determining the minimum number of Blue beads in any configuration, we must adhere to the given rules while arranging the beads. We have a 5x5 grid resulting in 25 cells. Each bead must be Red, Blue, or Green. The constraints are:
To minimize the number of Blue beads, we must consider the maximum use of Red and Green beads under these constraints. Analyzing the scenario:
Given the structure of a row or column:
Applying the constraints:
After trying logical patterns and minimal configurations ensuring these constraints are always followed, using at least six Blue beads is essential to satisfy all constraints across a grid.
| R | G | B | G | R |
| G | B | G | R | G |
| B | G | R | G | B |
| G | R | G | B | G |
| R | G | B | G | R |
This configuration, with strategic placement of Blue beads, ensures conditions are met minimally, thereby demanding at least 6 Blue beads. Hence, the minimum number of Blue beads in any configuration is 6.


| IPC crimes | SLL crimes | Other crimes | |
| Delhi | * | * | * |
| Goa | * | 4 | * |
| Haryana | 8 | 6 | * |
| Karnataka | 3 | 2 | * |
| Kerala | * | 9 | * |
| Maharashtra | 3 | 4 | 8 |
| Puducherry | 13 | 29 | * |
| Tamil Nadu | 11 | 7 | * |
| Telangana | 6 | 9 | 8 |
| West Bengal | 17 | * | 16 |
