| Sales Amounts (Crore Rupees) | ||||||||
|---|---|---|---|---|---|---|---|---|
| Delhi | Mumbai | Bengaluru | Kolkata | |||||
| 2018 | 2019 | 2018 | 2019 | 2018 | 2019 | 2018 | 2019 | |
| Apparels | 54 | |||||||
| Electronics | 78 | 98 | 82 | 102 | 90 | 70 | 80 | 100 |
| Home Decor | 100 | 72 | 80 | 54 | ||||
From 1, Consider 'a' as the sales amounts in the Apparel departments for Delhi and Kolkata in 2018.
From 2, Consider 'b' as the sales amounts in the Apparel departments for Mumbai, Bengaluru, and Delhi in 2018.
From 3, Consider 'c' as the sales amounts in the Home Decor departments for Mumbai and Kolkata in 2018 and that of Delhi and Bengaluru be s and t respectively.
Let the sales amounts in the Apparel departments for Mumbai and Bengaluru in 2019 be denoted by 'm' and 'n' respectively.
Now, the table will be as follows :
Sales Amounts (Crore rupees) | ||||||||
|---|---|---|---|---|---|---|---|---|
| Delhi | Mumbai | Bengaluru | Kolkata | |||||
| 2018 | 2019 | 2018 | 2019 | 2018 | 2019 | 2018 | 2019 | |
| Apparel | a | b | b | m | b | n | a | 54 |
| Electronics | 78 | 98 | 82 | 102 | 90 | 70 | 80 | 100 |
| Home Decor | s | 100 | c | 72 | t | 80 | c | 54 |
From 6, we get s = 80 and t = 60.
From 5, we have :
s + c + t + c + 70 = 306
⇒ 2c = 96
⇒ c = 48.
From 4, (b - a)+(m - b)+(n - b)+(54 - a)
=(20) + 20 - 20 + 20
⇒ 54 + m + n - 2a - b =40.
⇒ 2a + b =14 + m + n
⇒ 2b = 28 + 2m + 2n - 4a … (i)
From 7, b - a = n - b
⇒ 2b = a + n ...(ii) and m - b = 54 - a
⇒ a + m = 54 + b
⇒ 2b = 2a + 2m - 108 ...(iii)
From 8, 108 = b + n
⇒ 2b = 216 - 2n ...(iv)
From (i) and (ii), we get :
28 + 2m + 2n - 4a = 2a + 2m - 108
⇒ 6a = 136 + 2n
⇒ 3a = 68 + n ...(v)
From (ii) and (iv), we get :
216 - 2n = a + n.
⇒ a + 3n = 216
⇒ 3a = 648 - 9n ...(vi)
From (v) and (vi), we get :
648 - 9n = 68 + n
⇒ n = 58
⇒ a = 42
⇒ b = 50
⇒ m = 62
Final table will be as follows :
Sales Amounts (Crore rupees) | ||||||||
|---|---|---|---|---|---|---|---|---|
| Delhi | Mumbai | Bengaluru | Kolkata | |||||
| 2018 | 2019 | 2018 | 2019 | 2018 | 2019 | 2018 | 2019 | |
| Apparel | 42 | 50 | 50 | 62 | 50 | 58 | 42 | 54 |
| Electronics | 78 | 98 | 82 | 102 | 90 | 70 | 80 | 100 |
| Home Decor | 80 | 100 | 48 | 72 | 60 | 80 | 48 | 54 |
From the above table ,we can see that in 2018 and 2019, Delhi has the highest sales amount as 80 and 100 respectively.
So, the correct option is (A) : Delhi and Delhi.
From 1, Consider 'a' as the sales amounts in the Apparel departments for Delhi and Kolkata in 2018.
From 2, Consider 'b' as the sales amounts in the Apparel departments for Mumbai, Bengaluru, and Delhi in 2018.
From 3, Consider 'c' as the sales amounts in the Home Decor departments for Mumbai and Kolkata in 2018 and that of Delhi and Bengaluru be s and t respectively.
Let the sales amounts in the Apparel departments for Mumbai and Bengaluru in 2019 be denoted by 'm' and 'n' respectively.
Now, the table will be as follows :
| Sales Amounts (Crore rupees) | ||||||||
|---|---|---|---|---|---|---|---|---|
| Delhi | Mumbai | Bengaluru | Kolkata | |||||
| 2018 | 2019 | 2018 | 2019 | 2018 | 2019 | 2018 | 2019 | |
| Apparel | a | b | b | m | b | n | a | 54 |
| Electronics | 78 | 98 | 82 | 102 | 90 | 70 | 80 | 100 |
| Home Decor | s | 100 | c | 72 | t | 80 | c | 54 |
From 6, we get s = 80 and t = 60.
From 5, we have :
s + c + t + c + 70 = 306
⇒ 2c = 96
⇒ c = 48.
From 4, (b - a)+(m - b)+(n - b)+(54 - a)
=(20) + 20 - 20 + 20
⇒ 54 + m + n - 2a - b =40.
⇒ 2a + b =14 + m + n
⇒ 2b = 28 + 2m + 2n - 4a … (i)
From 7, b - a = n - b
⇒ 2b = a + n …....(ii)
and m - b = 54 - a
⇒ a + m = 54 + b
⇒ 2b = 2a + 2m - 108 …...(iii)
From 8, 108 = b + n
⇒ 2b = 216 - 2n …....(iv)
From (i) and (ii), we get :
28 + 2m + 2n - 4a = 2a + 2m - 108
⇒ 6a = 136 + 2n
⇒ 3a = 68 + n …....(v)
From (ii) and (iv), we get :
216 - 2n = a + n.
⇒ a + 3n = 216
⇒ 3a = 648 - 9n ….....(vi)
From (v) and (vi), we get :
648 - 9n = 68 + n
⇒ n = 58
⇒ a = 42
⇒ b = 50
⇒ m = 62
Final table will be as follows :
| Sales Amounts (Crore rupees) | ||||||||
|---|---|---|---|---|---|---|---|---|
| Delhi | Mumbai | Bengaluru | Kolkata | |||||
| 2018 | 2019 | 2018 | 2019 | 2018 | 2019 | 2018 | 2019 | |
| Apparel | 42 | 50 | 50 | 62 | 50 | 58 | 42 | 54 |
| Electronics | 78 | 98 | 82 | 102 | 90 | 70 | 80 | 100 |
| Home Decor | 80 | 100 | 48 | 72 | 60 | 80 | 48 | 54 |
From the table, we can see that, Apparel Department of Mumbai is having 62 and 50 sales, in Crore rupees in 2018 and 2019 respectively.
Increase in sales from 2018 to 2019 :
= 62 - 50
= 12
So, the correct option is (A) : 12.
From 1, Consider 'a' as the sales amounts in the Apparel departments for Delhi and Kolkata in 2018.
From 2, Consider 'b' as the sales amounts in the Apparel departments for Mumbai, Bengaluru, and Delhi in 2018.
From 3, Consider 'c' as the sales amounts in the Home Decor departments for Mumbai and Kolkata in 2018 and that of Delhi and Bengaluru be s and t respectively.
Let the sales amounts in the Apparel departments for Mumbai and Bengaluru in 2019 be denoted by 'm' and 'n' respectively.
Now, the table will be as follows :
| Sales Amounts (Crore rupees) | ||||||||
|---|---|---|---|---|---|---|---|---|
| Delhi | Mumbai | Bengaluru | Kolkata | |||||
| 2018 | 2019 | 2018 | 2019 | 2018 | 2019 | 2018 | 2019 | |
| Apparel | a | b | b | m | b | n | a | 54 |
| Electronics | 78 | 98 | 82 | 102 | 90 | 70 | 80 | 100 |
| Home Decor | s | 100 | c | 72 | t | 80 | c | 54 |
From 6, we get s = 80 and t = 60.
From 5, we have :
s + c + t + c + 70 = 306
⇒ 2c = 96
⇒ c = 48.
From 4, (b - a)+(m - b)+(n - b)+(54 - a)
=(20) + 20 - 20 + 20
⇒ 54 + m + n - 2a - b =40.
⇒ 2a + b =14 + m + n
⇒ 2b = 28 + 2m + 2n - 4a ….… (i)
From 7, b - a = n - b
⇒ 2b = a + n …....(ii)
and m - b = 54 - a
⇒ a + m = 54 + b
⇒ 2b = 2a + 2m - 108 …....(iii)
From 8, 108 = b + n
⇒ 2b = 216 - 2n …....(iv)
From (i) and (ii), we get :
28 + 2m + 2n - 4a = 2a + 2m - 108
⇒ 6a = 136 + 2n
⇒ 3a = 68 + n ….....(v)
From (ii) and (iv), we get :
216 - 2n = a + n.
⇒ a + 3n = 216
⇒ 3a = 648 - 9n ……...(vi)
From (v) and (vi), we get :
648 - 9n = 68 + n
⇒ n = 58
⇒ a = 42
⇒ b = 50
⇒ m = 62
Final table will be as follows :
| Sales Amounts (Crore rupees) | ||||||||
|---|---|---|---|---|---|---|---|---|
| Delhi | Mumbai | Bengaluru | Kolkata | |||||
| 2018 | 2019 | 2018 | 2019 | 2018 | 2019 | 2018 | 2019 | |
| Apparel | 42 | 50 | 50 | 62 | 50 | 58 | 42 | 54 |
| Electronics | 78 | 98 | 82 | 102 | 90 | 70 | 80 | 100 |
| Home Decor | 80 | 100 | 48 | 72 | 60 | 80 | 48 | 54 |
From the above table , we can see that Home decor department of Mumbai has got the highest percentage increase in sales from 2018 to 2019.
Percentage Increase = \(\frac{72-48}{48}\times100\)
\(=\frac{24}{48}\times100\)
\(=50\)
So, the correct option is (B) : 50.
From 1, Consider 'a' as the sales amounts in the Apparel departments for Delhi and Kolkata in 2018.
From 2, Consider 'b' as the sales amounts in the Apparel departments for Mumbai, Bengaluru, and Delhi in 2018.
From 3, Consider 'c' as the sales amounts in the Home Decor departments for Mumbai and Kolkata in 2018 and that of Delhi and Bengaluru be s and t respectively.
Let the sales amounts in the Apparel departments for Mumbai and Bengaluru in 2019 be denoted by 'm' and 'n' respectively.
Now, the table will be as follows :
| Sales Amounts (Crore rupees) | ||||||||
|---|---|---|---|---|---|---|---|---|
| Delhi | Mumbai | Bengaluru | Kolkata | |||||
| 2018 | 2019 | 2018 | 2019 | 2018 | 2019 | 2018 | 2019 | |
| Apparel | a | b | b | m | b | n | a | 54 |
| Electronics | 78 | 98 | 82 | 102 | 90 | 70 | 80 | 100 |
| Home Decor | s | 100 | c | 72 | t | 80 | c | 54 |
From 6, we get s = 80 and t = 60.
From 5, we have :
s + c + t + c + 70 = 306
⇒ 2c = 96
⇒ c = 48.
From 4, (b - a)+(m - b)+(n - b)+(54 - a)
=(20) + 20 - 20 + 20
⇒ 54 + m + n - 2a - b =40.
⇒ 2a + b =14 + m + n
⇒ 2b = 28 + 2m + 2n - 4a ….… (i)
From 7, b - a = n - b
⇒ 2b = a + n ….....(ii)
and m - b = 54 - a
⇒ a + m = 54 + b
⇒ 2b = 2a + 2m - 108 ……...(iii)
From 8, 108 = b + n
⇒ 2b = 216 - 2n ….....(iv)
From (i) and (ii), we get :
28 + 2m + 2n - 4a = 2a + 2m - 108
⇒ 6a = 136 + 2n
⇒ 3a = 68 + n ……...(v)
From (ii) and (iv), we get :
216 - 2n = a + n.
⇒ a + 3n = 216
⇒ 3a = 648 - 9n ….....(vi)
From (v) and (vi), we get :
648 - 9n = 68 + n
⇒ n = 58
⇒ a = 42
⇒ b = 50
⇒ m = 62
Final table will be as follows :
| Sales Amounts (Crore rupees) | ||||||||
|---|---|---|---|---|---|---|---|---|
| Delhi | Mumbai | Bengaluru | Kolkata | |||||
| 2018 | 2019 | 2018 | 2019 | 2018 | 2019 | 2018 | 2019 | |
| Apparel | 42 | 50 | 50 | 62 | 50 | 58 | 42 | 54 |
| Electronics | 78 | 98 | 82 | 102 | 90 | 70 | 80 | 100 |
| Home Decor | 80 | 100 | 48 | 72 | 60 | 80 | 48 | 54 |
From the above table ,we can see that the Departmental Stores has following sales amount in 2019 :
Delhi = 50 + 98 + 100 = 248
Mumabi = 62 + 102 + 72 = 236
Bengaluru = 58 + 70 + 80 = 208
Kolkata = 54 + 100 + 54 = 208
Therefore, total sales amount in 2019 = 248 + 236 + 208 + 208 = 900.
So, the correct option is (D) : 900.
The table provided displays the estimated cost (in lakh) for the construction of a canal between two points. Based on the information in the table, answer the questions that follow.
The following table gives the marks obtained by six students in six different subjects in an examination. The maximum marks for each subject are given in the brackets. Answer the questions that follow.
Consider the provided scenario and answer the following questions based on the given information.

