Question:
What is the mass of the substance 'X' required to prepare 250 mL of 0.5 molar aqueous solution? (Molar mass of 'X' is \(40 \mathrm{g} \mathrm{mol}^{- 1}\))
What is the mass of the substance 'X' required to prepare 250 mL of 0.5 molar aqueous solution? (Molar mass of 'X' is \(40 \mathrm{g} \mathrm{mol}^{- 1}\))
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Always convert volume to liters before using the molarity formula: M = n/V(L).
Updated On: Apr 24, 2026
- 2g
- 4g
- 5g
- 10g
- 0.5g
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The Correct Option is C
Solution and Explanation
Step 1: Understanding the Concept:
Molarity (M) = moles of solute volume of solution in liters. Mass = moles \(\times\) molar mass.
Step 2: Detailed Explanation:
Volume = 250 mL = 0.25 L. Molarity = 0.5 M.
Moles of X = M \(\times\) V(L) = \(0.5 \times 0.25 = 0.125\) moles.
Mass = moles \(\times\) molar mass = \(0.125 \times 40 = 5\) g.
Step 3: Final Answer:
The required mass is 5 g.
Molarity (M) = moles of solute volume of solution in liters. Mass = moles \(\times\) molar mass.
Step 2: Detailed Explanation:
Volume = 250 mL = 0.25 L. Molarity = 0.5 M.
Moles of X = M \(\times\) V(L) = \(0.5 \times 0.25 = 0.125\) moles.
Mass = moles \(\times\) molar mass = \(0.125 \times 40 = 5\) g.
Step 3: Final Answer:
The required mass is 5 g.
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