Question:

What is the major product formed when Propene reacts with \(HBr\) in the presence of peroxide?

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Remember: \(HBr\) in the presence of peroxide follows the Anti-Markovnikov rule (Peroxide Effect). This effect is observed only with \(HBr\), not with \(HCl\) or \(HI\).
Updated On: May 3, 2026
  • \(2\)-Bromopropane
  • \(1\)-Bromopropane
  • \(1,2\)-Dibromopropane
  • Propane
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The Correct Option is B

Solution and Explanation

Concept: In the presence of peroxide, the addition of \(HBr\) to an alkene follows the Anti-Markovnikov rule. According to this rule:
• The bromine atom attaches to the carbon having more hydrogen atoms.
• The hydrogen atom attaches to the more substituted carbon. This reaction proceeds through a free radical mechanism and is commonly known as the Peroxide Effect or Kharasch Effect.

Step 1:
Identify the structure of Propene. \[ CH_3 - CH = CH_2 \]

Step 2:
Apply the Anti-Markovnikov rule. The bromine atom attaches to the terminal carbon (which has more hydrogen atoms), leading to the formation of: \[ CH_3 - CH_2 - CH_2Br \]

Step 3:
Identify the product formed. \[ \text{Product: } 1\text{-Bromopropane} \]
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