Step 1: Understanding the Concept
In IUPAC naming an ether is an alkoxy alkane. The longer carbon chain is the parent and the shorter is the alkoxy group.
Step 2: Identify the parts
\(\text{CH}_3\text{-O-CH}_2\text{CH}_2\text{CH}_3\) has a three-carbon chain (propane) and one carbon on the other side of oxygen (methoxy).
Step 3: Number the chain
Number the propane chain from the end bearing the oxygen so the substituent gets the lowest number, which is carbon \(1\).
Step 4: Compare the options
The name is \(1\)-methoxypropane, option (A).
Final Answer:
The compound is 1-methoxypropane.
\[ \boxed{\text{(A) }\text{1-Methoxy propane}} \]