What is the intermediate product obtained in the preparation of phenol from aniline?
Benzene
Correct Answer: Option 2 - Benzene diazonium chloride
The preparation of phenol from aniline involves a two-step chemical process, and the key intermediate formed during this reaction is benzene diazonium chloride.
Step 1: Diazotization of Aniline
• In the first step, aniline (C6H5NH2) is reacted with nitrous acid (HNO2) in the presence of hydrochloric acid (HCl) at low temperatures (0–5°C).
• Nitrous acid is usually generated in situ by reacting sodium nitrite (NaNO2) with dilute HCl.
The reaction is:
C6H5NH2 + HNO2 + HCl → C6H5N2Cl + 2H2O
• The compound formed here is benzene diazonium chloride, which is a stable intermediate only at low temperatures.
Step 2: Hydrolysis to form Phenol
• In the second step, this intermediate benzene diazonium chloride is heated with water (hydrolysis), often in the presence of dilute acids.
• This decomposes the diazonium salt and releases nitrogen gas (N2), forming phenol (C6H5OH) as the final product.
The reaction is:
C6H5N2Cl + H2O → C6H5OH + N2 + HCl
Conclusion:
The intermediate product formed during the conversion of aniline to phenol is benzene diazonium chloride. This compound plays a critical role in many substitution reactions in aromatic chemistry and is an essential intermediate in organic synthesis.
From the following, how many compounds contain at least one secondary alcohol? 
Name the products formed when phenol is treated with the following reagents:
(i) Bromine water
(ii) Zinc dust
(iii) Conc. HNO_3
(i) Predict the products A and B in the hydroboration-oxidation reaction.
(ii) Explain the preparation of phenol from cumene.