Question:

What is the hybridization of carbon in an Ethyne (\(\mathrm{C_2H_2}\)) molecule?

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Number of sigma bonds around carbon determines hybridization: 2 sigma bonds \(\rightarrow sp\), 3 sigma bonds \(\rightarrow sp^2\), 4 sigma bonds \(\rightarrow sp^3\).
Updated On: Apr 21, 2026
  • \(sp^3\)
  • \(sp^2\)
  • \(sp\)
  • \(sp^3d\)
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The Correct Option is C

Solution and Explanation

Concept: Hybridization describes the mixing of atomic orbitals to form equivalent hybrid orbitals. In the ethyne molecule (\(\mathrm{C_2H_2}\)), each carbon atom forms a triple bond with another carbon atom and a single bond with hydrogen.

Step 1:
Determine the bonding around carbon. Each carbon forms:
• One \(\sigma\)-bond with hydrogen
• One \(\sigma\)-bond with the other carbon
• Two \(\pi\)-bonds between the carbon atoms

Step 2:
Count the regions of electron density. Each carbon has two regions of electron density (two \(\sigma\)-bonds).

Step 3:
Identify the hybridization. Two regions of electron density correspond to \(sp\) hybridization, giving a linear geometry with a bond angle of \(180^\circ\).
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