Step 1: Understanding the Concept
A primary alcohol is first oxidised to an aldehyde and then further to a carboxylic acid.
Step 2: Role of the Reagent
Acidified \(\text{K}_{2}\text{Cr}_{2}\text{O}_{7}\) is a strong oxidising agent, so the oxidation does not stop at the aldehyde.
Step 3: Write the Sequence
\(\text{RCH}_{2}\text{OH}\rightarrow \text{RCHO}\rightarrow \text{RCOOH}\). The final product is a carboxylic acid, option (C).
Final Answer:
The final product is a carboxylic acid.
\[ \boxed{\text{(C) }\text{carboxylic acid}} \]