What is the equivalent resistance between the points A and B of the network?

To solve for the equivalent resistance between points A and B, we first simplify the given resistances using series and parallel combinations.
Start by analyzing the network step by step: 1. Combine the resistances that are in series. 2. Combine the resistances that are in parallel. Once simplified, the equivalent resistance turns out to be 8 \( \Omega \).
Final Answer: 8 \( \Omega \).
In the given circuit, the electric currents through $15\, \Omega$ and $6 \, \Omega$ respectively are

A wire of resistance 0.2 \( \Omega/{cm} \) is bent to form a square ABCD of side 10 cm. A similar wire is connected between the corners B and D. If 2 V battery is connected across A and C, the power dissipated is
