The total voltage gain of the cascaded amplifiers is the product of their individual gains: \[ {Total Gain} = 10 \times 20 = 200 \] Now, multiply the input signal by the total gain: \[ {Output signal} = 0.01 \times 200 = 2 \, {V} \] Thus, the output AC signal is 2 V.
Final Answer: 2 V.
In the given circuit, the electric currents through $15\, \Omega$ and $6 \, \Omega$ respectively are

What is the equivalent resistance between the points A and B of the network?

A wire of resistance 0.2 \( \Omega/{cm} \) is bent to form a square ABCD of side 10 cm. A similar wire is connected between the corners B and D. If 2 V battery is connected across A and C, the power dissipated is
