Question:
What is the difference in terms of molar masses of second and fourth members of homologous series?
What is the difference in terms of molar masses of second and fourth members of homologous series?
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Consecutive homologues differ by CH2 (14 g/mol), so the 2nd and 4th differ by two CH2 units.
Updated On: Oct 1, 2026
- \(12\)
- \(24\)
- \(28\)
- \(36\)
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The Correct Option is C
Solution and Explanation
Step 1: Understanding the Concept:
A homologous series is a family of compounds in which each member differs from the next by one \(-\text{CH}_2-\) unit.
Step 2: Find the mass of one CH2 unit:
\(12 + 2(1) = 14\) g/mol.
Step 3: Count the steps:
From the second member to the fourth member, there are two steps (second to third, third to fourth). So two \(-\text{CH}_2-\) groups are added.
Step 4: Calculate the difference:
\(2 \times 14 = 28\) g/mol.
Step 5: Why the other options are wrong.
12 is the mass of one C atom only. 24 is two C atoms and ignores hydrogen. 36 would mean about three CH2 units counted with a wrong mass.
Final Answer:
The difference in molar mass is 28. \[ \boxed{\text{(C) }28} \]
A homologous series is a family of compounds in which each member differs from the next by one \(-\text{CH}_2-\) unit.
Step 2: Find the mass of one CH2 unit:
\(12 + 2(1) = 14\) g/mol.
Step 3: Count the steps:
From the second member to the fourth member, there are two steps (second to third, third to fourth). So two \(-\text{CH}_2-\) groups are added.
Step 4: Calculate the difference:
\(2 \times 14 = 28\) g/mol.
Step 5: Why the other options are wrong.
12 is the mass of one C atom only. 24 is two C atoms and ignores hydrogen. 36 would mean about three CH2 units counted with a wrong mass.
Final Answer:
The difference in molar mass is 28. \[ \boxed{\text{(C) }28} \]
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